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Raul Ramirez Vs Peter Fleming • Roterdão 1979

Roterdão 1979, ATP 5001/4 finais
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Raul Ramirez
RamirezRaul 4
5
3
0
0
0
Peter Fleming
FlemingPeter
7
6
0
0
0
1
Borg B.
Cox M.
64 62
Schneider D.
Sanders L.
16 63 63
Kriek J.
Q
Crealy D.
76 62
Reininger R.
6
Clerc J.
76 63
4
Ramirez R.
Q
Feaver J.
64 67 75
Mitton B.
Kronk P.
76 67 76
Amritraj A.
Fleming P.
63 76
Dupre P.
8
Mottram B.
61 36 63
7
Fibak W.
Pinner U.
61 62
Joubert D.
Franulovic Z.
26 61 61
Okker T.
Mayer G.
63 75
Gunthardt H.
3
McEnroe J.
62 61
5
Nastase I.
Gehring R.
76 57 64
Pattison A.
Amritraj V.
75 62
Teacher B.
Masters G.
62 64
Feigl P.
2
Gerulaitis V.
61 64
1
Borg B.
Sanders L.
63 62
Kriek J.
6
Clerc J.
64 62
4
Ramirez R.
Kronk P.
62 75
Fleming P.
8
Mottram B.
63 64
7
Fibak W.
Franulovic Z.
64 62
Mayer G.
3
McEnroe J.
64 61
Gehring R.
Amritraj V.
76 63
Masters G.
2
Gerulaitis V.
67 64 62
1
Borg B.
Kriek J.
64 62
4
Ramirez R.
Fleming P.
75 63
7
Fibak W.
3
McEnroe J.
63 61
Amritraj V.
2
Gerulaitis V.
61 76
1
Borg B.
Fleming P.
62 62
3
McEnroe J.
Amritraj V.
60 63
1
Borg B.
3
McEnroe J.
64 62
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